12x^2=4x*(1+3x)-16

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Solution for 12x^2=4x*(1+3x)-16 equation: 


Simplifying
12x2 = 4x(1 + 3x) + -16
12x2 = (1 * 4x + 3x * 4x) + -16
12x2 = (4x + 12x2) + -16

Reorder the terms:
12x2 = -16 + 4x + 12x2

Add '-12x2' to each side of the equation.
12x2 + -12x2 = -16 + 4x + 12x2 + -12x2

Combine like terms: 12x2 + -12x2 = 0
0 = -16 + 4x + 12x2 + -12x2

Combine like terms: 12x2 + -12x2 = 0
0 = -16 + 4x + 0
0 = -16 + 4x

Solving
0 = -16 + 4x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x' to each side of the equation.
0 + -4x = -16 + 4x + -4x
Remove the zero:
-4x = -16 + 4x + -4x

Combine like terms: 4x + -4x = 0
-4x = -16 + 0
-4x = -16

Divide each side by '-4'.
x = 4

Simplifying
x = 4

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